limn→∞19+29+........n9n10=limn→∞∑nr=1r9n10
=limn→∞∑nr=11n(rn)9=∫10x9dx
=(x1010+c)10
=110
Evaluate the following :
(i) ∑11n=1(2+3n)
(ii) ∑nk=1(2k+3k−1)
(iii) ∑10n=24n