wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following using identities:​
​v. (1.5x20.3y2)(1.5x2+0.3y2)

Open in App
Solution

Given: (1.5x20.3y2)(1.5x2+0.3y2)

Using the identity,(ab)(a+b)=a2b2

(1.5x20.3y2)(1.5x2+0.3y2)=(1.5x2)2(0.3y2)2=2.25x40.09y4

Hence, (1.5x20.3y2)(1.5x2+0.3y2)=2.25x40.09y4

flag
Suggest Corrections
thumbs-up
13
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon