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Byju's Answer
Standard XII
Mathematics
Quadratic Equation
Evaluate the ...
Question
Evaluate the following using identities:
v.
(
1.5
x
2
−
0.3
y
2
)
(
1.5
x
2
+
0.3
y
2
)
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Solution
Given:
(
1.5
x
2
−
0.3
y
2
)
(
1.5
x
2
+
0.3
y
2
)
Using the identity,
(
a
−
b
)
(
a
+
b
)
=
a
2
−
b
2
∴
(
1.5
x
2
−
0.3
y
2
)
(
1.5
x
2
+
0.3
y
2
)
=
(
1.5
x
2
)
2
−
(
0.3
y
2
)
2
=
2.25
x
4
−
0.09
y
4
Hence,
(
1.5
x
2
−
0.3
y
2
)
(
1.5
x
2
+
0.3
y
2
)
=
2.25
x
4
−
0.09
y
4
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