Evaluate (102)3 using suitable identities
Given expression can be written as
(102)3=(100+2)3
We know that (a+b)3=a3+b3+3ab(a+b)
⇒(100+2)3=(100)3+(2)3+3×100×2(100+2)=1000000+8+600(102)=1000000+8+61200=1061208
Hence we get 1061208 after simplification.