Evaluate the following using suitable identities:
(998)3 [2 MARKS]
Formula: 1 Mark
Application: 1 Mark
(998)3=(1000−2)3
Using the identity
(x−y)3=x3−y3−3xy(x−y)
=(1000)3−(2)3−3(100)(2)(1000−2)
=1000000000−8−600(998)
=1000000000−8−598800
=1000000000−598808
=999401192