Evaluate- 25-15 - - 8 - 12 - 7 - 1 - 3 -

Solving given expression by solving brackets first⇒ ( 25 15 ) × [ 8+12+{ 7 1+3 }]0ex0ex=10 × [ 20 + 9 ]0ex0ex=10 × 290ex0ex= 290Hence we get 290 after simpl ...

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Standard VI

Mathematics

BODMAS

Evaluate: 25-...

Question

Evaluate: $(25 - 15) \times [8 + 12 + {7 - 1 + 3}]$

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Solution

Solving given expression by solving brackets first
$\Rightarrow (25 - 15) \times [8 + 12 + {7 - 1 + 3}] = 10 \times [20 + 9] = 10 \times 29 = 290$
Hence we get $290$ after simplification

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Similar questions

Q. Evaluate 7

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|− 15| − |− 9|

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Evaluate:
(i) $(- 6) \times (- 15) \times (- 5)$

(ii) $(- 8) \times (- 5) \times 9$

(iii) $9 \times (- 12) \times 10$

(iv) $(- 75) \times 8$

(v) $(- 5) \times (- 5) \times (- 5) \dots \dots$ taken $5$ times

(vi) $(- 1) \times (- 1) \times (- 1) \dots \dots$ taken $25$ times

Q. Determine each of the following products:
(i) 12 ☓ 7
(ii) (−15) ☓ 8
(iii) (−25) ☓ (−9)
(iv) 125 ☓ (−8)

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(a) 12 + [{1 + (15 − 3)} × 4]

(b)

(c)

(d)

(e)

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(i) (−16) × 12 + (−16) × 8
(ii) 25 × (−33) + 25 × (−17)
(iii) (−19) × (−25) + (−19) × (−15)
(iv) (−47) × 68 − (−47) × 38
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(vi) (−168) ÷ (−14)
(vii) 0 ÷ (−34)
(viii) 37 ÷ 0

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Evaluate: (25-15)×[8+12+{7–1+3}]

Solving given expression by solving brackets first⇒(25-15)×[8+12+{7-1+3}]=10×[20+9]=10×29=290Hence we get 290 after simplification

Evaluate: $(25 - 15) \times [8 + 12 + {7 - 1 + 3}]$

Solving given expression by solving brackets first
$\Rightarrow (25 - 15) \times [8 + 12 + {7 - 1 + 3}] = 10 \times [20 + 9] = 10 \times 29 = 290$
Hence we get $290$ after simplification