Question

Evaluate the given limit :
$\underset{x\to 0}{lim}\frac{\cos x}{\pi -x}$

Answer 1

Given : $\underset{x\to 0}{lim}\frac{\cos x}{\pi -x}$
Substituting $x=0$
$=\frac{\cos 0}{\pi -0}$
$=\frac{\cos 0}{\pi }$
$=\frac{1}{\pi }$
$\therefore \underset{x\to 0}{lim}\frac{\cos x}{\pi -x}=\frac{1}{\pi }$