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Question

Evaluate the integral
10sin1xxdx

A
π log2
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B
π log2
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C
π2 log2
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D
π2 log2
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Solution

The correct option is C π2 log2
Put x=sinθ and adjust the limits
I=π/20θsinθcosθdθ=π/20θcotθdθ.
Integrate by parts
I=[θlogsinθ]π/20π/20logsinθ.1dθ
=(π2.0)limθ0(θlogsinθ)π2log12
=0+π2log2

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