Question

Evaluate the integral ${\int }_0^{\frac{\pi }{2}}\sin xdx$

• A. $0$
• B. $-1$
• C. $1$
• D. $2$

Answer 1

The correct option is C $1$

Given, ${\int }_0^{\frac{\pi }{2}}\sin xdx$
$\Rightarrow {[-\cos x]}_0^{\frac{\pi }{2}}=[-\cos \frac{\pi }{2}-(-\cos 0\left)\right]=1$