Question

Evaluate the integral $\int \frac{(x^2+2)}{x+1}dx$

Answer 1

I = $\int \frac{x^2+2}{x+1}dx=\int \frac{(x^2-1)+3}{x+1}dx=\int (x-1+\frac{3}{x+1})dx=\int (x-1)dx+3\int \frac{1}{x+1}dx=\frac{x^2}{2}-x+3log\left|\right(x+1\left)\right|+C$