MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

First Fundamental Theorem of Calculus

Evaluate the ...

Question

Evaluate the integrals
$\int_{1}^{2} (x^{2} + 2 x + 2) d x$

Open in App

Solution

$\int_{1}^{2} (x^{2} + 2 x + 2) d x$ = ${(\frac{x^{3}}{3} + x^{2} + 2 x)}_{1}^{2}$

$\Rightarrow (\frac{8 - 1}{3}) + (4 - 1) + 2 (2 - 1)$

$\Rightarrow \frac{7}{3} + 5$

$= \frac{22}{3}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Evaluate the following integrals:

\int \frac{x^{2}}{x^{4} + x^{2} - 2} d x

Q. Evaluate the integrals

\int_{1}^{2} \frac{1}{(x^{2} + 2 x)} d x

Q. Evaluate the following integrals

\int \frac{x^{2}}{{(a^{2} - x^{2})}^{3 / 2}} d x

Q. Evaluate the following integrals:

\int_{- 4}^{4} |x + 2| d x

Q. Evaluate the following integrals:

\int \frac{x^{2} + x + 1}{(x^{2} + 1) (x + 2)} d x

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Fundamental Theorem of Calculus

MATHEMATICS

Watch in App

explore_more_icon

Explore more

First Fundamental Theorem of Calculus

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon