Question

Evaluate the integrals
${\int }_3^4(x^2-9)dx$

Answer 1

${\int }_3^4(x^2-9)dx$$={(\frac{x^3}{3}-9x)}_3^4$

$\Rightarrow \frac{1}{3}(4^3-3^3)-9(4-3)$

$\Rightarrow \frac{37}{3}-9$

$=\frac{10}{3}$