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Question

Evaluate the limit:
limx0ax+bx+cx3x

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Solution

Given:
limx0ax+bx+cx3x

=limx0ax1+bx1+cx1x

=limx0(ax1x+bx1x+cx1x)

=limx0(ax1x)+limx0(bx1x)+limx0(cx1x)

=loga+logb+logc[limx0(ax1x)=loga]

=log(abc) [logM+logN=logMN]

Therefore,
limx0ax+bx+cx3x=log(abc)

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