wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the limit:
limx0sin 3xsin xsin x

Open in App
Solution

limx0sin 3xsin xsin x

=limx0sin 3x3x×3xsin xx×xsin xx×x

=limx01×3x1×x1×x [limx0sin xx=1]

=2

Therefore,

limx0sin 3xsin xsin x=2

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon