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Byju's Answer
Standard XII
Mathematics
Summation Using Sigma
Evaluate the ...
Question
Evaluate the limit:
lim
x
→
∞
3
x
−
1
+
4
x
−
2
5
x
−
1
+
6
x
−
2
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Solution
We have,
lim
x
→
∞
3
x
−
1
+
4
x
−
2
5
x
−
1
+
6
x
−
2
It becomes
0
0
form.
On multiplying numerator and denominator by
x
, we get
=
lim
x
→
∞
3
+
4
x
−
1
5
+
6
x
−
1
=
lim
x
→
∞
3
+
4
x
5
+
6
x
Where
x
→
∞
, then
1
x
→
0
=
3
+
4
(
0
)
5
+
6
(
0
)
=
3
5
Therefore,
lim
x
→
∞
3
x
−
1
+
4
x
−
2
5
x
−
1
+
6
x
−
2
=
3
5
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5
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Summation Using Sigma
Standard XII Mathematics
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