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Question

Evaluate the limit:
limx3x1+4x25x1+6x2

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Solution

We have,
limx3x1+4x25x1+6x2

It becomes 00 form.

On multiplying numerator and denominator by x, we get

=limx3+4x15+6x1

=limx3+4x5+6x

Where x, then 1x0

=3+4(0)5+6(0)=35

Therefore,
limx3x1+4x25x1+6x2=35

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