limx→3(x2−9)(1x+3+1x−3)
(0×∞)form
limx→3,(x2−9)(1x+3−1x−3)
limx→3(x2−9)((x−3)+(x+3)(x+3)(x−3))
⇒limx→3(x2−9)(2xx2−9)
⇒limx→3(2x)
=2×3=6
Therefore,
⇒limx→3(x2−9)(1x+3+1x−3)=6