CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the limit to infinity
limx(3x1)(4x2)(x+8)(x1)[12]

Open in App
Solution

limx(3x1)(4x2)(x+8)(x1)

=limxx2(31x)(42x)x2(1+8x)(11x)

=3×41×1=12

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation and Rationalisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon