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Question

Evaluate the mentioned below:

(v)2x4+5x3+7x2x+41,whenx=23i


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Solution

Given that-
x=23i
x+2=3i
(x+2)2=(3i)2squaringonbothside
x2+4x+7=0(1)
2x4+5x3+7x2x+41
=2x2(x2+4x+7)3x37x2x+41
=2x2(x2+4x+7)3x(x2+4x+7)+5x2+20x+41
=2x2(x2+4x+7)3x(x2+4x+7)+5(x2+4x+7)+6
=2x2×03x×0+5×0+6fromeqn(1)
=6
Therefore,2x4+5x3+7x2x+41=6


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