Question

Evaluate the square root of $96$ in radical form

Answer 1

Step 1: Prime factorizing given number

The first step is to divide the number $96$ with the smallest prime factor, say $2$ and then by other factors till we get $1$

So, $96=2\times 2\times 2\times 2\times 2\times 3$

Step 2: Finding square root by pairing the factors

For this, we make pairs and take that number one time outside the square root.

Whatever number that is not in pair, keep inside the root.

$$\begin{gathered} \Rightarrow \sqrt{96}=\sqrt{(2\times 2)\times (2\times 2)\times 2\times 3} \\ \Rightarrow \sqrt{96}=2\times 2\sqrt{6} \\ \Rightarrow \sqrt{96}=4\sqrt{6} \end{gathered}$$

Hence, the square root of $96$ is $4\sqrt{6}$