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Byju's Answer
Standard XII
Mathematics
Substitution Method to Remove Indeterminate Form
Evaluate x⟶...
Question
Evaluate
l
i
m
x
⟶
π
6
2
−
√
3
c
o
s
x
−
s
i
n
x
(
6
x
−
π
)
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Solution
l
i
m
x
⟶
π
6
2
−
√
3
c
o
s
x
−
s
i
n
x
(
6
x
−
π
)
it is of the form
0
0
So, We can apply L-Hospital Rule
l
i
m
x
⟶
π
6
0
+
√
3
sin
x
−
cos
x
6
=
√
3
∗
1
2
−
√
3
2
6
=
0
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0
Similar questions
Q.
l
i
m
x
→
π
6
3
s
i
n
x
−
√
3
c
o
s
x
6
x
−
π
=
Q.
Solve :
lim
x
→
π
6
(
3
sin
x
−
√
3
cos
x
6
x
−
π
)
=
Q.
lim
x
→
π
6
(
3
sin
x
−
√
3
cos
x
6
x
−
π
)
Q.
Prove that
f
(
x
)
=
s
i
n
x
+
√
3
c
o
s
x
has maximum value at
x
=
π
6
.
Q.
lim
x
→
π
6
3
sin
x
−
√
3
cos
x
6
x
−
π
=
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