wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate limx0logsinxx

Open in App
Solution

Solution -
limx0log(sinxx)
We know that limx0sinxx=1
=log(1)
=0

1092225_1179780_ans_1606c637eca641ba8555e24cdb10f133.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction to Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon