wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate using identities 6393+33

A
486
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
486
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
86
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 486
We know that a3b3=(ab)(a2+ab+b2)

6393+93

=(69)(62+6×9+92)+33

=3(36+54+81)+33

=513+33

=486

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Finding Perfect Squares CV
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon