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Question

Evaluate without actual multiplication.
999×999

A
998001
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B
998021
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C
989001
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D
None of the above
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Solution

The correct option is D 998001
The value of 999×999 is
=(10001)(10001)
=(10001)2
We know that suitable identities (xy)2=x22xy+y2
Thus (10001)2 =(1000)22(1000)(1)+(1)2
=10000002000+1
=998001

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