Question

Evaluate :

$x^2+4x+4÷(x+2)$ and find the quotient and remainder.

Answer 1

We have,

$x^2+4x+4÷x+2=\frac{x^2+4x+4}{x+2}$

$=\frac{x^2+2x+2x+4}{x+2}$

$=\frac{x(x+2)+2(x+2)}{x+2}$

$=\frac{(x+2)(x+2)}{x+2}$

$=x+2$

Hence,

The quotient $=x+2$

The remainder $=0$