Evaluate (x + y + z)2
x2 + y2 + z2 + 2xy +2yz +2zx
x2 + y2z2 + 2xy + 2yz – 2zx
x2 – y2 – z2 + 2xy – 2yz – 2zx
x2 + y2 + z2 + 2xy + 2yz
(x + y + z)2 = x2+ y2 + z2 + 2xy + 2yz + 2zx
2x³ +2y³ +2z³- 6xyz= (x+y+z) [(x-y)² +(y-z)² +(z-x)² ] hence evaluate 2(7)³ +(9)³ + 2(13)³ -6(7)(9)(13).