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Question

Evaluate:

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Solution

We have the following expression,

[ i 18 + ( 1 i ) 25 ] 3

We know that, i= 1 .

Therefore, i 2 =1 and i 4 =1 .

i 18 = i 4×4+2 = i 2 =1

And

1 i = 1 i × i i = i i 2 =i

Simplifying further

( 1 i ) 25 = ( i ) 25 = ( i ) 4×6+1 =i

Hence,

[ i 18 + ( 1 i ) 25 ] 3 = [ 1i ] 3 =[ 1+ i 3 +3× 1 2 ×i+3×1× i 2 ] =[ 1i+3i3 ] =2[ 1i ]

Thus, [ i 18 + ( 1 i ) 25 ] 3 =2[ 1i ] .


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