Evaluate
i) $(38)^{2} - (37)^{2}$
ii) $(75)^{2} - (74)^{2}$
iii) $(141)^{2} - (140)^{2}$

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Solution

(i)
$(38)^{2} - (37)^{2}$
Using $a^{2} - b^{2} = (a + b) (a - b)$ we get,
$= (38 + 37) (38 - 37)$
$= (75) (1)$
$= 75$
(ii)
$(75)^{2} - (74)^{2}$
Using $a^{2} - b^{2} = (a + b) (a - b)$ we get,
$= (75 + 74) (75 - 74)$
$= (149) (1)$
$= 149$
(iii)
$(141)^{2} - (140)^{2}$
Using $a^{2} - b^{2} = (a + b) (a - b)$ we get,
$= (141 + 140) (141 - 140)$
$= (281) (1)$
$= 281$

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Evaluatei)(38)2−(37)2ii)(75)2−(74)2iii)(141)2−(140)2

(i)(38)2−(37)2Using a2−b2=(a+b)(a−b) we get,=(38+37)(38−37)=(75)(1)=75(ii)(75)2−(74)2Using a2−b2=(a+b)(a−b) we get,=(75+74)(75−74)=(149)(1)=149(iii)(141)2−(140)2Using a2−b2=(a+b)(a−b) we get,=(141+140)(141−140)=(281)(1)=281

Evaluate
i) $(38)^{2} - (37)^{2}$
ii) $(75)^{2} - (74)^{2}$
iii) $(141)^{2} - (140)^{2}$