Evaluates - 13-1 - 15-1 - 16-1

( 13 )^ 1+ ( 15 )^ 1 ( 16 )^ 1 =31+51 61 #160; #160; #160; #160; #160; #160; ( x^ 1 =1x ) =8 6=2 ...

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Byju's Answer

Standard VI

Mathematics

Addition of Fractions

Evaluates : ...

Question

Evaluates : ${(\frac{1}{3})}^{- 1} + {(\frac{1}{5})}^{- 1} - {(\frac{1}{6})}^{- 1}$

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Solution

${(\frac{1}{3})}^{- 1} + {(\frac{1}{5})}^{- 1} - {(\frac{1}{6})}^{- 1}$

$= \frac{3}{1} + \frac{5}{1} - \frac{6}{1}$ $(x^{- 1} = \frac{1}{x})$

$= 8 - 6 = 2$

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Evaluates : (13)−1+(15)−1−(16)−1

(13)−1+(15)−1−(16)−1=31+51−61 (x−1=1x)=8−6=2

Evaluates : ${(\frac{1}{3})}^{- 1} + {(\frac{1}{5})}^{- 1} - {(\frac{1}{6})}^{- 1}$

${(\frac{1}{3})}^{- 1} + {(\frac{1}{5})}^{- 1} - {(\frac{1}{6})}^{- 1}$

$= \frac{3}{1} + \frac{5}{1} - \frac{6}{1}$ $(x^{- 1} = \frac{1}{x})$

$= 8 - 6 = 2$