Question

Evaluates the following.
$\frac{(-14{)}^4\times {11}^3\times 6}{7^3\times {12}^2\times 121}$

Answer 1

Given expression:

$\frac{(-14{)}^4\times {11}^3\times 6}{7^3\times {12}^2\times 121}=\frac{7^4\times 2^4\times {11}^3\times 6}{7^3\times {12}^2\times {11}^2}$

$=\frac{7^4\times 2^3\times {11}^3\times 12}{7^3\times {12}^2\times {11}^2}$

$=\frac{7\times 2^3\times 11}{12}$ (since, $\frac{a^m}{a^n}=a^{m-n}$)

$=\frac{7\times 2\times 11}{3}=\frac{154}{3}=51.33$