Evaluates the following- 70 - 120 - 170570 - 450 - 130

Given expression: 7^0× 12^0× 17^057^0+(45^0× 13^0)=1× 1× 11+(1× 1) (since, a^0=1 ) =11+1= 12 ...

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Standard VIII

Mathematics

Numbers in General Form

Evaluates the...

Question

Evaluates the following.
$\frac{7^{0} \times 12^{0} \times 17^{0}}{57^{0} + (45^{0} \times 13^{0})}$

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Solution

Given expression:
$\frac{7^{0} \times 12^{0} \times 17^{0}}{57^{0} + (45^{0} \times 13^{0})} = \frac{1 \times 1 \times 1}{1 + (1 \times 1)}$ (since, $a^{0} = 1$ )
$= \frac{1}{1 + 1} = \frac{1}{2}$

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Q. In a junior football league, the heights of players and the number of goals scored by them are tabulated. Identify the height class which contains the top scorer.

\begin{matrix} H e i g h t (i n c m) & 100 - 110 & 110 - 120 & 120 - 130 & 130 - 140 & 140 - 150 & 150 - 160 & 160 - 170 & 170 - 180 N o . o f g o a l s s c o r e d & 8 & 10 & 15 & 9 & 12 & 14 & 13 & 10 \end{matrix}

The median of the following data is:

$\begin{matrix} I Q & 60 - 70 & 70 - 80 & 80 - 90 & 90 - 100 & 100 - 110 & 110 - 120 & 120 - 130 N o . o f p u p i l s & 2 & 3 & 5 & 16 & 14 & 13 & 7 \end{matrix}$

Q. Find the missing frequency of the mean of the data is

154

Classes	$120 - 130$	$130 - 140$	$140 - 150$	$150 - 160$	$160 - 170$	$170 - 180$
Frequency	$2$	$8$	$12$	$f$	$8$	$7$

The median for the data is

$\begin{matrix} IQ & 60 - 70 & 70 - 80 & 80 - 90 & 90 - 100 & 100 - 110 & 110 - 120 & 120 - 130 No. of pupils & 2 & 3 & 5 & 16 & 14 & 13 & 7 \end{matrix}$

Q. Find the mean of each of the following frequency distributions :

Class interval:	50-70	70-90	90-110	110-130	130-150	150-170
Frequency:	18	12	13	27	8	22

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Evaluates the following. 70×120×170570+(450×130)

Given expression:70×120×170570+(450×130)=1×1×11+(1×1) (since, a0=1)=11+1=12

Evaluates the following.
$\frac{7^{0} \times 12^{0} \times 17^{0}}{57^{0} + (45^{0} \times 13^{0})}$

Given expression:
$\frac{7^{0} \times 12^{0} \times 17^{0}}{57^{0} + (45^{0} \times 13^{0})} = \frac{1 \times 1 \times 1}{1 + (1 \times 1)}$ (since, $a^{0} = 1$ )
$= \frac{1}{1 + 1} = \frac{1}{2}$