Question

Evalute :

(ii) $\frac{2}{3}+\frac{-4}{5}-\frac{1}{3}-\frac{2}{5}$

Answer 1

Step : Evaluate

$\frac{2}{3}+\frac{-4}{5}-\frac{1}{3}-\frac{2}{5}=\frac{2}{3}-\frac{1}{3}-\frac{4}{5}-\frac{2}{5}$

$=\frac{2-1}{3}+\frac{-4-2}{5}$

$=\frac{1}{3}+\frac{(-6)}{5}$

$=\frac{1}{3}-\frac{6}{5}$

$=\frac{1\times 5}{3\times 5}-\frac{6\times 3}{5\times 3}$

(LCM of 3 and 5 is 15)

$=\frac{5}{15}-\frac{18}{15}$

$=\frac{5-18}{15}$

$=\frac{-13}{15}$

Hence, $\frac{2}{3}+\frac{-4}{5}-\frac{1}{3}-\frac{2}{5}=\frac{-13}{15}$