Evalute the following expression (x2)2x−6−(2x−6)x2 for x=3.
A
9
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B
6
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C
1
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D
0.0
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Solution
The correct option is C 1 (x2)2x−6=x2×(2x−6)(∵(am)n=amn) =x4x−12 Since x=3, (x2)2x−6=x4x−12 =34(3)−12 =312−12 =30 =1(∵a0=1) Also, (2x−6)x2=(2(3)−6)32 =(6−6)9 =0. ∴(x2)2x−6−(2x−6)x2=1−0=1