Events $E_{1}, E_{2}, E_{3}$ are the possible events of an experiment and their probabilities are recorded. Mark the possible correct answer

$P (E_{1}) = 0.3, P (E_{2}) = 0.4, P (E_{3}) = 0.4$

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$P (E_{1}) = 0.1, P (E_{2}) = 0.4, P (E_{3}) = 0.5$

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$P (E_{1}) = 0.6, P (E_{2}) = - 0.3, P (E_{3}) = 0.7$

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$P (E_{1}) = 0.4, P (E_{2}) = 0.2, P (E_{3}) = 0.3$

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Solution

The correct option is B
$P (E_{1}) = 0.1, P (E_{2}) = 0.4, P (E_{3}) = 0.5$

$P (E_{1}) = 0.1 P (E_{2}) = 0.4 P (E_{3}) = 0.5 P (E_{1}) + P (E_{2}) + P (E_{3}) = (0.1) + (0.4) + (0.5) = 1.0$

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