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Range and Sum of Probabilities

Events E 1, E...

Question

Events $E_{1}, E_{2}, E_{3}$ are the possible outcomes of an experiment and their probabilities are recorded. Mark the possible correct answer.

P (E_{1})

= 0.4

P (E_{2})

= 0.2

P (E_{3}) = 0.3

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P (E_{1})

= 0.6

P (E_{2})

= - 0.3

P (E_{3})

= 0.7

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P (E_{1})

= 0.1

P (E_{2})

= 0.4

P (E_{3})

= 0.5

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P (E_{1})

= 0.3

P (E_{2})

= 0.4

P (E_{3})

= 0.4

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Solution

The correct option is C $P (E_{1})$ = 0.1
$P (E_{2})$ = 0.4
$P (E_{3})$ = 0.5
Sum of all the probabilities of different outcomes for an event is always 1.
$P (E_{1})$ = 0.1
$P (E_{2})$ = 0.4
$P (E_{3})$ = 0.5

$P (E_{1})$ + $P (E_{2})$ + $P (E_{3})$ = (0.1) + (0.4) + (0.5) = 1.0

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Similar questions

E_{1}, E_{2}, E_{3}

Events $E_{1}, E_{2}, E_{3}$ are the possible events of an experiment and their probabilities are recorded. Mark the possible correct answer

E_{1} a n d E_{2}

P (E_{1}) = P (E_{2}); P (E_{1} \cup E_{2}) = 1; E_{1} a n d E_{2}

P (E_{1}) =

E_{1}, E_{2}, E_{3}

E_{1}

E_{2}

P (E_{1}) = \frac{1}{4}, P (\frac{E_{2}}{E_{1}}) = \frac{1}{2}

P (\frac{E_{1}}{E_{2}}) = \frac{1}{4},

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