Every series of hydrogen spectrum has an upper andlower limit in wavelength. The spectral series which has an upper limit of wavelength equal to 18752∘A is
A
Balmer series
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B
Lyman series
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C
Paschen series
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D
Pfund series
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Solution
The correct option is CPaschen series 1λ=R[1n21−1n22]]⇒1n21−1n22=1Rλ=11.097×107×18752×10−10=0.0486=7144But132−142=7144⇒n1=3andn2=4(Paschenseries)