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Ex. Q7. Balan...

Question

Ex. Q7. Balance the following equation stepwise.

$c . Ag (s) + HCl (aq) \to AgCl ⏐ ↓ + H_{2} ↑ ⏐ d . NaOH (aq) + H_{2} {SO}_{4} (aq) \to {Na}_{2} {SO}_{4} (aq) + H_{2} O (l)$

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Solution

c)
Balanced equation: $2 Ag + 2 HCl 2 AgCl + H_{2}$
Explanation:
⇒ Step 1: Write the given unbalanced equation
$Ag + HCl AgCl + H_{2}$

⇒ Step 2: Compare the number of atoms of reactants with the number of atoms of products.

Reactants (left side) Products (right side)

Element Number of atoms Number of atoms

Ag 1 1

H 1 2

Cl 1 1

⇒ Step 3: Now, First we consider the element having unequal no. of atoms on both sides . Thus, let us consider hydrogen atom. If we multiply 2 in the reactant (in HCl), we will get the equa number of atoms as in product ( $H_{2}$ )

No of atoms of oxygen Reactants (in HCl
) Products
(in $H_{2} O$ )

Initially 1 2

To balance $1 \times 2 = 2$ 2

⇒ Step 4: Write the resulting equation:
$Ag + 2 HCl \to AgCl + H_{2}$

⇒ Step 5: Now check whether the equation is balanced or not by comparing the atoms

Reactants (left side) Products (right side)

Element Number of atoms Number of atoms

Ag 1 1

H 2 2

Cl 2 1

We find that the equation is not balanced yet. As the number of Chlorine atom is unequal on the two sides.
First balance the hydrogen number.

No of atoms of oxygen Reactants (in ${SO}_{2}$ ) Products
(in $H_{2} O$ )

Initially 2 1

To balance 2 $1 \times 2 = 2$

We find that the equation is not balanced yet. As the number of Sulphur and hydrogen atoms are unequal on the two sides.
First balance the hydrogen number.

⇒ Step 6: Now, let us consider chlorine atom. If we multiply 2 in the product (in AgCl), we will get the equal number of atoms as in reactant (in HCl)

No of atoms of Chlorine Reactants (in HCl) Products
(in AgCl)

Initially 2 4

To balance 2 $1 \times 2 = 2$

⇒ Step 7: Write the resulting equation:
$Ag + 2 HCl \to 2 AgCl + H_{2}$

⇒ Step 8: Now check whether the equation is balanced or not by comparing the atoms

Reactants (left side) Products (right side)

Element Number of atoms Number of atoms

Ag 1 2

H 2 2

Cl 2 2

We find that the equation is not balanced yet. As the number of Silver atom is unequal on the two sides.

⇒ Step 9: Now, let us consider silver atom. If we multiply 2 in the reactant (Ag), we will get the equal number of atoms as in product (AgCl)

No of atoms of Hydrogen Reactants (in Ag) Products
(in AgCl)

Initially 1 2

To balance $1 \times 2$ 2

⇒ Step 10: Write the resulting equation:
$2 Ag + 2 HCl \to 2 AgCl + H_{2}$
⇒ Step 11: Now, compare the atoms of both the sides of all the elements. Write down the final balanced equation:
$2 Ag + 2 HCl \to 2 AgCl + H_{2}$

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