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Ideal Gas Equation

Exactly 100 m...

Question

Exactly 100 mL of oxygen is collected over water of $13^{o} C$ and 800 mm pressure. Calculate the volume of dry oxygen at NTP. (Vapour pressure of water at $23^{o} C$ is 21 mm)

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Solution

$P_{g a s} = P_{a t m} - P_{w a t e r} = 800 - 21 P_{g a s} = 779 m m .$
Now combination of boyles law & charls law.
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} V_{2} = \frac{P_{1} V_{1} T_{2}}{T_{1} P_{2}} V_{2} = \frac{100 \times 779 \times 293}{296 \times 760} V_{2} = 101.46 m m .$
volume of dry oxygen at NTP.

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