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Question

Examine the following functions for continuity :

f(×)=×225×+5,x×not=5

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Solution

f(×)=×225×+5=(×+5)(×5)(×+5)=×5

f(×)=×5 is a polynomial function, so f(x) is continuous at all values of x.

Note In any rational function f(x)=p(x)q(x) and if P(x) and q(x) are polynomials and q(x) is zero at any value of x and p(x) = 0, then f(x) is not continuous at that point.


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