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Question

Examine whether following vectors are coplanar or not. a+b2c,a3b+c and 2abc .

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Solution

If the vectors are coplanar then area of the triangle formed by them must be zero.
Therefore,
∣ ∣112131211∣ ∣ = 1(3+1)1(12)+2(16) = 3
Hence, area is 3 sq. units.
Therefore, the given vectors are not coplanar.

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