Given, a∗b=ab+1
(i) Since a,b∈R, ab will belong to R
i.e., ab∈R
⇒ab+1∈R
So, a∗b is a binary operation.
(ii) The binary operation will be associative if
(a∗b)∗c=a∗(b∗c) ∀ a,b,c∈R
Consider (a∗b)∗c=(ab+1)∗c
=(ab+1)c+1=abc+c+1
a∗(b∗c)=a∗(bc+1)
=a(bc+1)+1=abc+a+1
Here, we can see that
(a∗b)∗c≠a∗(b∗c) ∀ a,b,c∈R
So, it is not associative.