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Question

Examine whether x2 is a factor of 2x33x25x+6 or not using factor theorem.

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Solution

Let p(x)=2x33x25x+6.

Put divisor equal to 0,

x2=0

x=2

Put the value of x in p(x),

p(2)=2(2)33(2)25(2)+6

=161210+6

=0

Since the remainder is 0, so, x2 is the factor of 2x33x25x+6.


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