You visited us 8 times! Enjoying our articles? Unlock Full Access!

Sucrose

Excess of aci...

Question

Excess of acidified solution of KI was added to 30mL H2O2 solution. The iodine liberated required 25mL of 0.4 N Na2S2O3 solution. The volume strength of H2O2 solution is?

Open in App

Solution

$T h e t i t r a t i o n w a s d o n e i n d i r e c t l y w i t h H y d r o g e n p e r o x i d e a n d t h i o s o l u t i o n u \sin g K I . V_{1} N_{1} = V_{2} N_{2} 30 \times N_{1} = 25 \times 0.4 N_{1} = \frac{25 \times 0.4}{30} = 0.333 N V o l u m e s t r e n g t h = N o r m a l i t y \times 5.6 = 0.333 \times 5.6 = 1.867$

Suggest Corrections

Similar questions

H_{2} O_{2}

N a_{2} S_{2} O_{3}

H_{2} O_{2}

25 m l

H_{2} O_{2}

K I

20 m l

0.3 N

{N a}_{2} S_{2} O_{3}

H_{2} O_{2}

K I

25

H_{2} O_{2}

20

0.3 N N a_{2} S_{2} O_{3}

H_{2} O_{2}

25

H_{2} O_{2}

K I

20

0.1 N

N a_{2} S_{2} O_{3}

H_{2} O_{2}

25

H_{2} O_{2}

20

0.3

H_{2} O_{2}

Join BYJU'S Learning Program