Excess of isobutane on reaction with Br2 in presence of light at 125oC gives which one of the following, as the major product?
A
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B
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C
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D
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Solution
The correct option is A Halogenation alkane undergoes free radical mechanism.
Tertiary free radicals are more stable tha primary,
Hence, C−H bond breaking is favourable in tertiary carbon and thus, it gives the major product as shown below: