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Chemical Properties of Alcohol

Excess of KI ...

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Excess of KI reacts with 25ml H_2O_2 solution to produce iodine . The liberated iodine requires 10ml of 0.3N sodium thiosulphate solution for complete reaction .Find the normality of H_2O_2

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25

H_{2} O_{2}

solution, excess of an acidified solution of potassium iodide was added. The iodine liberated required

20

0.3

N sodium thiosulphate solution.

Calculate the volume strength of

H_{2} O_{2}

solution (to the nearest integer):

25

H_{2} O_{2}

solution were added to excess of acidified

K I

solution. The iodine so liberated required

20

0.1 N

N a_{2} S_{2} O_{3}

for titration. Calculate strength of

H_{2} O_{2}

in terms of normality and percentage?

Q. An excess of acidified solution of

K I

25

H_{2} O_{2}

solution. The iodine liberated requires

20

0.3 N N a_{2} S_{2} O_{3}

solution. Calculate the volume strength of

H_{2} O_{2}

:

50

ml of an aqueous solution of

H_{2} O_{2}

were treated with an excess of

K I

solution and dilute

H_{2} S O_{4}

. The liberated iodine required

20

0.1

N N a_{2} S_{2} O_{3}

solution for complete interaction. The concentration of

H_{2} O_{2}

25 m L H_{2} O_{2}

were added to excess of acidified solution of

K I

. The iodine so liberated required

20 m L

0.1 N

sodium thiosulphate for titration. Calculate the strength in terms of normality percentage and volume.

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