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Question

Excess of KI reacts with CuSO4 solution, and Na2S2O3 solution is added to it. Which of the following statements is incorrect for the reaction?

A
Evolved I2 is reduced
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B
CuI2 is formed
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C
Na2S2O3 is oxidised
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D
Cu2I2 is formed
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Solution

The correct option is B CuI2 is formed
The statement (B) is incorrect.
Cu2I2 and not CuI2 is formed.
KI reacts with copper sulphate to forn cuprous iodide
2CuSO4+4KICu2I2+2K2SO4+I2
The liberated iodide is reduced with sodium thiosulphate which itself is oxidized.
I2+2Na2S2O32NaI+Na2S4O6

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