Question

Excess of $P{Cl}_5$ reacts with conc. $H_{2}S{O}_4$ giving:

• A. chlorosulphonic acid
• B. thionyl chloride
• C. sulphuryl chloride
• D. sulphurous acid

Answer 1

Answer: (B)

thionyl chloride

Excess of $PC{l}_5$ reacts with $H_{2}S{O}_4$ to form thionyl chloride ($S{O}_{2}C{l}_2$), phosporyl chloride and hydrochloric acid.

$H_{2}S{O}_4+2PC{l}_5\to S{O}_{2}C{l}_2+2POC{l}_3+HCl$.

Hence, option $B$ is correct.