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Question

Excess of silver nitrate solution is added to 100mL of 0.01M pentaaqua chloro chromium (III) chloride solution. The mass of silver chloride obtained in grams is:

[Atomic mass of silver is 108]

A
287×103
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B
143.5×103
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C
143.5×102
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D
287×102
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Solution

The correct option is B 287×103
[Cr(H2O5)Cl]Cl2 is the reagent
i.e. 2Cl() can be combined with Ag to give AgCl
mass of AgCl ppt,
no. of moles of Cl()=2×100×0.011000=0.002
moles of AgCl ppt=0.002
mass of AgCl=0.002×143.5
=2.87×103g

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