Excess pressure of one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one is:

1:64

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64:1

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4:1

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1:2

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Solution

The correct option is C 1:64
Excess pressure = $Δ P = \frac{4 T}{R}$
$Δ P_{A} = 4 Δ P_{B}$
So, $\frac{Δ P_{A}}{Δ P_{B}} = 4 = \frac{4 T / R_{A}}{4 T / R_{B}} = \frac{R_{B}}{R_{A}}$
Now volume is proportional to $(r a d i u s)^{3}$
So, $\frac{V_{A}}{V_{B}} = (\frac{R_{A}}{R_{B}})^{3} = (\frac{1}{4})^{3} = \frac{1}{64}$

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The excess pressure of one soap bubble is four times more than other. Than the ratio of volume of the first bubble to another is

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