Expand 1 - 3x2 - 6x3-2-3 as far as x5-

(1+3x^2 6x^3)^ 2/3 = 1 23(3x^2 6x^3)+( 23) ( 53) 1· 2 (3x^2 6x^3)^2 …… = 1 2x^2+4x^3+59(9x^4 36x^5+…)+ … #160;= 1 2x^2 +4x^3 +5x^4 20x^5 ...

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Sum of Infinite Terms of a GP

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Question

Expand $(1 + 3 x^{2} - 6 x^{3})^{- \frac{2}{3}}$ as far as $x^{5}$ .

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Solution

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