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Question

Expand: ((2x−1)2)2−36x2

A
(4x210x+1)(4x2+2x+1)
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B
(4x210x+1)(4x32x+1)
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C
(4x210x+1)(4x24x+1)
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D
(4x210x1)(4x22x1)
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Solution

The correct option is B (4x210x+1)(4x2+2x+1)
[(2x1)2]236x2=(4x24x+1)2(6x)2

=(4x24x+16x)(4x24x+1+6x), since a2b2=(ab)(a+b)

=(4x210x+1)(4x2+2x+1), simplify

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